Show data from a one-to-many relationship

I have 2 tables with a one-to-many relationship.

Table 1:

_________________
| id | question  | 
|____|___________|
|  1 | question1 |
|  2 | question2 |
|____|___________|

Table 2:

______________________________
| id | answer  | question_id |
|____|_________|_____________|
|  1 | answer1 |      1      |
|  2 | answer2 |      1      |
|____|_________|_____________|

While question_id is the foreign key.

I’m trying to show the data like that:

      question1
answer1     answer2

So question then the answers for this particular question.

Here is the code I have:

$query = "SELECT questions.*, answers.* FROM questions INNER JOIN answers ON questions.id = answers.question_id";

$run = mysqli_query($connect, $query);

while($data = mysqli_fetch_assoc($run)){
    echo $data['question'] . '<br>';
    echo $data['answer'] . '<br>';
}

This returns:

question1
answer1
question1
answer2

So how to show the question only once with the related answers to this particular question?

Answer

MySQL’s GROUP_CONCAT function might come in handy here:

$query = <<<QUERY
SELECT q.question, GROUP_CONCAT(a.answer ORDER BY q.id) answers
FROM questions q
         INNER JOIN answers a ON q.id = a.question_id
GROUP BY q.question
QUERY;

$run = mysqli_query($connect, $query);

while ($data = mysqli_fetch_assoc($run)) {
    echo htmlspecialchars($data['question'], ENT_QUOTES | ENT_HTML5), "<br>n";
    $answers = explode(',', $data['answers']);

    echo '<pre>';
    for ($i=0, $iMax = count($answers); $i < $iMax; $i++) {
        if ($i > 0) echo "<br>n";
        echo '&nbsp;&nbsp;&nbsp;&nbsp;', htmlspecialchars($answers[$i], ENT_QUOTES | ENT_HTML5);
    }
    echo '</pre>';
}