# How to skip certain array indexes? Code Answer

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Need to sort only odd values in array, but even values must remain on their places.

Here is my code:

public static int[] sortArray(int[] array) {

int length = array.length;
int temp = 0;

for (int i = 0; i < length; i++) {
for (int j = 1; j < length - i; j++) {
if (j > 0 && array[j] % 2 == 0)continue;

if (array[j - 1] > array[j]){
temp = array[j - 1];
array[j - 1] = array[j];
array[j] = temp;
}
}
}

return array;
}

input: new int[]{5, 3, 2, 8, 1, 4, 0}

output: [1, 3, 5, 2, 8, 4, 0]

but I need: [1, 3, 2, 8, 5, 4, 0]

How to skip certain indexes in array?

Think this should be connected with continue operator, but I don’t know how to do it.

public static int[] sortArray(int[] array) {

int length = array.length;

for (int i = 0; i < length - 1; i++) {
int k = -1; // The index of last odd element
for (int j = 0; j < length - i; j++)
if (array[j] % 2 != 0) {
if (k >= 0 && array[k] > array[j]) {
int temp = array[k];
array[k] = array[j];
array[j] = temp;
}
k = j;
}
}

return array;
}