public static boolean oneNumeric(String s) {
String[] digit = {"0","1", "2", "3", "4", "5", "6" ,"7", "8", "9"};
boolean numeric = true;
for (int i=0; i< s.length(); i++) {
if(!(s.contains(digit[i]))) {
return false;
}}
return numeric;
}
I want to return true or false into my main method, but it won’t work in the for loop. I’m confused.
What am I doing wrong?
Answer
To make your method right, you should
- remove useless
numericvariable - use
digit.lengthas upper bound, as you access thedigitarray - remove the
!and returntrue
It’ll will check, for each digit, if it is present in the string, if no one is in the string, return false
public static boolean oneNumeric(String s) {
String[] digit = {"0","1", "2", "3", "4", "5", "6" ,"7", "8", "9"};
for (int i=0; i< digit.length; i++) {
if(s.contains(digit[i])) {
return true;
}
}
return false;
}
But an easier method would be :
public static boolean oneNumeric(String s) {
return s.matches(".*\d.*"); // 'd' is for digit in regex
}