# Big O for a loop vs a javasccript method that solves a problem [closed]

Find if the two arrays contain a similar property or value.

```const one =[1,2,3,4,5]
const two = [5,6,7,8]
```
```// a double loop that solves this problem
O(n^2)
```

VS

```two.some(item => one.includes(item))
// this is more efficient than the double loop method
// but behind the scenes isnt javascript just looping ?
// why is this more performant ?
// and is the big O  of this O(n)?
```

If your

a double loop that solves this problem

breaks out of the loops as soon as a match is found, then both methods are similarly inefficient – they both require iterating over all of N elements M times, worst-case, where N is the length of one array and M is the length of the other. (So, `O(n * m)`, or `O(n^2)`, depending on how you want to specify the lengths of the inputs.)

The advantage to the second method

```two.some(item => one.includes(item))
```

is that it’s a lot more readable than using `for` loops. It’s not more performant – the opposite is true, `for` loops are generally faster than array methods.

If you wanted to reduce the complexity to `O(n)`, instead of iterating over the second array inside a loop, use a Set lookup inside the loop, which is much faster:

```const oneSet = new Set(one);
return two.some(item => oneSet.has(item));
```

because set lookup is sublinear, and generally O(1) – resulting in an overall complexity of `O(n)`.