I’ve got some Python code that runs through a list of strings and converts them to integers or floating point numbers if possible. Doing this for integers is pretty easy
if element.isdigit(): newelement = int(element)
Floating point numbers are more difficult. Right now I’m using
partition('.') to split the string and checking to make sure that one or both sides are digits.
partition = element.partition('.') if (partition.isdigit() and partition == '.' and partition.isdigit()) or (partition == '' and partition == '.' and partition.isdigit()) or (partition.isdigit() and partition == '.' and partition == ''): newelement = float(element)
This works, but obviously the if statement for that is a bit of a bear. The other solution I considered is to just wrap the conversion in a try/catch block and see if it succeeds, as described in this question.
Anyone have any other ideas? Opinions on the relative merits of the partition and try/catch approaches?
I would just use..
try: float(element) except ValueError: print "Not a float"
..it’s simple, and it works. Note that it will still throw OverflowError if element is e.g. 1<<1024.
Another option would be a regular expression:
import re if re.match(r'^-?d+(?:.d+)$', element) is None: print "Not float"