# Find minor matrix in python Code Answer

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```def getMatrixMinor(m,i,j):
return [row[:j] + row[j+1:] for row in (m[:i]+m[i+1:])]
```

The above is the code that I find on the stack overflow in order to find the inverse of a matrix, however, I am really new in python. Can anybody explain the behind mechanism in order to construct a matrix of minor by using this code?

By the way, I’ve used this code and it works but I just don’t understand how it works.

Let’s start with the definition of `(i,j)th` minor matrix of a matrix:

`(i,j)th` minor of a matrix of size `n` is a smaller matrix of size `n-1` with the `i'th` row and `j'th` column deleted.

Now lets look at this python one liner:

```[row for row in (m[:i] + m[i+1:])]
```

`m[:i]` gives the first `i` rows of `m` (remember that we are representing a matrix as a list of rows, and adding two lists gives back a bigger list in python), now let’s look at another one liner:

```row[:j] + row[j+1:]
```

This gives us all the elements of a row except the `j'th` element (lst[a:b] gives a list with elements from `lst` between `a` and `b`, with `b` excluded)

Combine the above two and you get an expression which returns `a new matrix with i'th row and j'th column excluded`:

```def getMatrixMinor(m,i,j):
return [row[:j] + row[j+1:] for row in (m[:i]+m[i+1:])]
```

Which is the minor matrix.