Currently i’m studying data science, and really start this from zero i’m trying to practice several things on Python right now
in this case i’m getting a category and should create a bundle
list_category = ['c1','c2','c3','c4','c5','c6','c7','c8','c9','c10']
and in this context i want to get the result with this expectation:
a. not getting the same result in the bundle e.g
b. one bundle is allowed getting same two category e.g
c. same result with different order isn’t allowed e.g (
c1 - c2 - c3 = c2 - c1 - c3)
i tried to using this code, but apparently i’m still getting a lot of same result
list_category = ['c1','c2','c3','c4','c5','c6','c7','c8','c9','c10'] bundling_list =  for i in list_category: category1 = i for y in list_category: if i != y: category2 = y for c in list_category: if c != y: category3 = c bundling = i + '-' + y + '-' + c bundling_list.append(bundling) print(bundling_list)
tried to google some, but i didn’t get my expected answer so far, is there anyway to solve this Thanks!
Just import random module from python and use random.choice method to select a random item from your list.Then by creating a new list by avoiding that selected item.In this way 3 unique items can be collected from a list.
- You can also simply delete items chosen using random from the list thereby avoiding creation of 2 extra lists.
I Think This may help you 🙂
import random list_category = ['c1','c2','c3','c4','c5','c6','c7','c8','c9','c10'] l2= l3= n1=random.choice(list_category) for i in list_category: if i!=n1: l2.append(i) n2=random.choice(l2) for i in l2: if i!=n2: l3.append(i) n3=random.choice(l3) bundle="-".join([n1,n2,n3]) print(bundle)