I AM USING PYCHARM TO RUN THIS AS IT IS A REQUIREMENT FROM OUR PROFESSOR
The Periodic Table of the Elements was developed to organize information about the elements that make up the Universe. Write a python program that lets you enter information about each element in the periodic table. Make sure you include the following information: symbol, name, atomic number, row, and column Provide a menu of options for users to: See all the information that is stored about any element, by entering that element’s symbol. Choose a property and see that property for each element in the table.
I have the below code
class element:
def __init__(self, sym, name, no, typ, row, col):
self.symbol = sym
self.name = name
self.atomic_number = no
self.elem_type = typ
self.row = row
self.column = col
def viewElement(element, n):
print("Name: " + element.name)
if n == 2 or n == 3:
print("Symbol: " + element.symbol)
if n == 2 or n == 4:
print("Atomic Number: " + str(element.atomic_number))
if n == 2 or n == 5:
print("Type: " + element.elem_type)
if n == 2 or n == 6:
print("Row: " + str(element.row))
if n == 2 or n == 7:
print("Column: " + str(element.column))
print("n")
if __name__ == "__main__":
elem_dict = {}
while 1:
print("n Main Menu n")
print("1. Add an Element")
print("2. View an Element")
print("3. View all Element Names")
print("4. View all Atomic Numbers")
print("5. View all Types")
print("6. View all Row Numbers")
print("7. View all Column Number")
print("8. Exit")
choice = int(input("Enter your Choice: "))
if choice == 1:
sym = input("Enter the symbol: ")
name = input("Enter the element name: ")
atom = int(input("Enter the atomic number: "))
typ = input("Enter the element type: ")
row = int(input("Enter the row number: "))
col = int(input("Enter the column number: "))
if sym not in elem_dict.keys():
e1 = element(sym, name, atom, typ, row, col)
elem_dict[sym] = e1
print(sym + " addedn")
else:
print("Element already present")
elif choice == 2:
sym = input("Enter the symbol: ")
viewElement(elem_dict[sym], 2)
elif choice == 3:
for i in elem_dict.keys():
viewElement(elem_dict[i], 3)
elif choice == 4:
for i in elem_dict.keys():
viewElement(elem_dict[i], 4)
elif choice == 5:
for i in elem_dict.keys():
viewElement(elem_dict[i], 5)
elif choice == 6:
for i in elem_dict.keys():
viewElement(elem_dict[i], 6)
elif choice == 7:
for i in elem_dict.keys():
viewElement(elem_dict[i], 7)
elif choice == 8:
print("Exiting")
break
else:
print("Wrong entry, Please re-entern")
I keep getting the below error when I chose option 1 and get the the last part
Main Menu
- Add an Element
- View an Element
- Viel all Element Names
- View all Atomic Numbers
- View all Types
- View all Row Numbers
- View all Column Number
- Exit
Enter your Choice: 1
Enter the symbol: H
Enter the element name: Hydrogen
Enter the atomic number: 1
Enter the element type: Gas
Enter the row number: 1
Enter the column number: 1
Traceback (most recent call last):
File "C:/Users/stephanie/Desktop/LEGRANGE_UNIT_SEVEN/Periodic_Table.py",
line 51, in <module>
e1 = element(sym, name, atom, typ, row, col)
TypeError: element() takes no arguments
Process finished with exit code 1
Answer
You need to change the init method to a dunder (__init__):
def __init__(self, sym, name, no, typ, row, col): # Notice the double underscore either side of init
Otherwise the class will not initialize because your init is just a self defined method inside the class.