I am currently trying to write a script in Bash that can run a set of unit/integration tests. I have that part working, but what I need now is to be able to output a summary at the end. I have been trying to use grep ot grab every line which contains a number followed by the string failing, save it in a variable, and print it at the end.
So an example of a failing output is
224 passing (3m) 47 failing
What I would like to be printed at the end is something along the lines of
service01 4 failing service03 1 failing
What I have so far is:
OUTPUT=""
for service in ${array[*]}
do
echo $service
if [ $DO_API == 'true' ]
then
echo 'running API tests'
OUTPUT+="$service API $(docker exec -it $service npm run api_test | tee /dev/tty | grep -e '[0-9]+ failing' )"
fi
if [ $DO_CI == 'true' ]
then
echo 'running CI tests'
OUTPUT+="$service CI $(docker exec -it $service npm run ci | tee /dev/tty | grep -e '[0-9]+ failing' )"
fi
echo $'n'
done
The above script shows no output when there are failing tests, which leads me to believe it is my grep syntax at fault.
What am I doing wrong?
Answer
The following grep command will return the required output:
grep -E '[0-9]+ failing'
The pattern [0-9]+ matches one or more digits. The -E option must be used so that grep can interpret the pattern as an extended regular expression. The + quantifier is not defined as part of the basic regular expressions.
Sample run (using a file):
$ cat testfile 224 passing (3m) 47 failing $ grep -E '[0-9]+ failing' testfile 47 failing
As an aside, this pattern can also be implemented using basic regular expressions (BRE) in the following manner:
$ grep '[0-9]{1,} failing' testfile
47 failing
In this case, the {n,m} quantifier is used to match one or more digits. The backslashes are required to give the curly braces their special meaning.