Generating strings of words with space delimiters from cut statement

I am new to bash. When I run the following command:

grep "type" /root/myFile | cut-d'=' -f2

I get the following:


I want to store the contents of the first command into a variable such that the content of the variable would be the equivalent of declaring it like this:

myVariable="102 304 503 442"

I don’t know how to go about this. Do I initialize myVariablewith an empty string and traverse the content of the command line-by-line and append it into myVariable with white spaces in between or is there an easier way for doing this with bash?


myVariable=`grep "type" /root/myFile | cut-d'=' -f2`

What is between back-ticks (`) is run and the output is assigned to myVariable.

If your current output is separated by line feeds (n), then you may want to replace them with spaces with tr such as:

myVariable=`grep "type" /root/myFile | cut-d'=' -f2`|tr 'n' ' '`

Note: Some people prefer using the $() syntax instead of back-ticks but both are useful and when I have the choice I use the back-ticks. The real advantage of having both is if you want to handle execution at two levels since the back-ticked expression will be sent to a sub-shell first and then the $() portion will be executed.

Leave a Reply

Your email address will not be published. Required fields are marked *