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For example, there are some temperature data at those folders in different time.
temps.txt contains the temperature number. So how can I use bash script to find out the maximum temperature? (the results only show the date,time and number of temperature,e.g. ./2011.10.20/00:00/temps.txt 27C).
$ ls 2011.10.20 2012.01.20 2012.04.16 2012.07.12 2012.10.07 2011.10.21 2012.01.21 2012.04.17 2012.07.13 2012.10.08 2011.10.22 2012.01.22 2012.04.18 2012.07.14 2012.10.09 $ cd 2011.10.20 $ ls 00:00 02:25 04:50 07:15 09:40 12:05 14:30 16:55 19:20 21:45 00:05 02:30 04:55 07:20 09:45 12:10 14:35 17:00 19:25 21:50 00:10 02:35 05:00 07:25 09:50 12:15 14:40 17:05 19:30 21:55 $ cd 00:00 $ ls temps.txt $ cat temps.txt Sensor Location Temp ------ -------- ---- #1 PROCESSOR_ZONE 27C/80F
Answer
You can use the combination find, grep and awk command to get the desired result. The below is a oneliner which will print the file which has the maximum temperature recorded.
find . -mindepth 3 -exec echo -n "{} " ; -exec grep "PROCESSOR_ZONE" {} ; |
awk '{
split($4,val,"/");
gsub("C","",val[1]);
if (max<val[1]) {file=$1; max=val[1]}
} END {print(file)}'
Output
./2012.04.16/00:10/temps.txt
Below is the script version of the oneliner.
#!/bin/bash
# The path where temperature directories and files are kept
path="/tmp/tmp.ADntEuTlUT/"
# Temp file
tempfile=$(mktemp)
# Get the list of files name and their corresponding
# temperature data.
find "${path}" -mindepth 3 -exec echo -n "{} " ; -exec grep "PROCESSOR_ZONE" {} ; > "${tempfile}"
# Parse though the temp file to find the maximum
# temperature based on Celsius
awk '{split($4,val,"/");gsub("C","",val[1]);if(max<val[1]){file=$1;max=val[1]}} END{print(file)}' "${tempfile}"
# Removing the temp file
rm -f "${tempfile}"
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