How to remove a line from a tag in shell script? Code Answer

We have an xml file (abc_lop.xml) in which I need to remove a line which is present in a tag:

Below is an xml file, I have shorten it down as it is very big.

<HELLO version="4.2" xmlns="http://www.bacd.org/HELLO-4_2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.bacd.org/HELLO-4_2 http://www.bacd.org/v4-2/hello-4-2.xsd">


    <!-- some data here  -->

</HELLO>

As you can see I have this line xsi:schemaLocation="http://www.bacd.org/HELLO-4_2 http://www.bacd.org/v4-2/hello-4-2.xsd" in HELLO tag above. I need to remove this line and keep other stuff.

As of now I am adding some header and footer to the above xml file which is shown below in my shell script and then storing it in file variable: Here $word is abc.

file=$(printf '%sn%sn%s' "$header" "$(cat "$path/${word}_lop.xml")" "$footer")

Now I want to make sure file variable should have xml file data but with that line remove as well from HELLO tag.

I am using this $file variable later on for some other purpose so I want to make sure $file should have header, footer and that line removed as well. That line which has key=value pair will only be present once.

Answer

To remove the xsi:schemaLocation entry, leaving the rest of the file intact:

$ sed 's/xsi:schemaLocation="[^"]*"//' "$path/${word}_lop.xml"
<HELLO version="4.2" xmlns="http://www.bacd.org/HELLO-4_2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >


    <!-- some data here  -->

</HELLO>

s/xsi:schemaLocation="[^"]*"// is a substitute command. It replaces anything matching the regex xsi:schemaLocation="[^"]*" with nothing.

To combine this with your script:

file=$(printf '%sn%sn%s' "$header" "$(sed 's/xsi:schemaLocation="[^"]*"//' "$path/${word}_lop.xml")" "$footer")