Linux Pocket Guide has a nice example on how to go over all the arguments in a script
for arg in [email protected] do echo "I found the argument $arg" done
I am writing a script in which all the arguments will be text files, and I will concatenate all those text files and print them to stdout, however I should exclude the contents of the first argument. My first approach would be something like this
for arg in [email protected] do cat "$arg" done
However, that will include the first argument, and as I mentioned, I want to print all except the first one.
You can use
shift command like this:
shift for arg in "[email protected]" do cat "$arg" done