Is it possible to use member function call as default argument?
Here is my code: struct S { int f() { return 1; } int g(int arg = f()) { return arg; } }; int main() { S s; return s.g(); } This fails to compile with the error: error: cannot call …
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Here is my code: struct S { int f() { return 1; } int g(int arg = f()) { return arg; } }; int main() { S s; return s.g(); } This fails to compile with the error: error: cannot call …
I want to declare type definition for a member function signature. Global function typedefs look like this: typedef int (function_signature)(int, int); typedef int (*function_pointer) (int, int); But …